$$\frac{t-32}{180}=\frac{c-0}{100}=\frac{2x-2}{180}; =\frac{x-0}{100}$$
$\frac{t-32}{180}=\frac{c}{100}\text{ and }\frac{c}{100}=\frac{x-1}{90}$
$x=\frac{9c}{10}+1$
$t=\frac{9c}{5}+32$
$t=2\left(x+15\right)$
$c=\frac{10x-10}{9}$
