Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac{ w-3 }{ { w }^{ 2 } +w } - \frac{ 8 }{ 2w+1 }$$

Answer

$$(-6*w^2-13*w-3)/(w*(w+1)*(2*w+1))$$

Solution


Factor out the common term \(w\).
\[\frac{w-3}{w(w+1)}-\frac{8}{2w+1}\]
Rewrite the expression with a common denominator.
\[\frac{(w-3)(2w+1)-8w(w+1)}{w(w+1)(2w+1)}\]
Expand.
\[\frac{2{w}^{2}+w-6w-3-8{w}^{2}-8w}{w(w+1)(2w+1)}\]
Collect like terms.
\[\frac{(2{w}^{2}-8{w}^{2})+(w-6w-8w)-3}{w(w+1)(2w+1)}\]
Simplify  \((2{w}^{2}-8{w}^{2})+(w-6w-8w)-3\)  to  \(-6{w}^{2}-13w-3\).
\[\frac{-6{w}^{2}-13w-3}{w(w+1)(2w+1)}\]
[email protected]
Privacy Policy | Terms & Conditions
Contact Us