Question

$$\frac{ w+4 }{ 3 { w }^{ 2 } } + \frac{ { w }^{ 2 } +4 }{ 3 { w }^{ 2 } }$$

Answer

$$(w+8+w^2)/(3*w^2)$$

Solution


Join the denominators.
\[\frac{w+4+{w}^{2}+4}{3{w}^{2}}\]
Collect like terms.
\[\frac{w+(4+4)+{w}^{2}}{3{w}^{2}}\]
Simplify  \(w+(4+4)+{w}^{2}\)  to  \(w+8+{w}^{2}\).
\[\frac{w+8+{w}^{2}}{3{w}^{2}}\]