Solve x/2 + y/3 = 8; - 3y = - 3 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{x}{2}+\frac{y}{3}=8; -3y=-3$$

Solve for x, y

$x = \frac{46}{3} = 15\frac{1}{3} \approx 15.333333333$
$y=1$

Solution Steps

Consider the second equation. Divide both sides by $-3$.

$$y=\frac{-3}{-3}$$

Divide $-3$ by $-3$ to get $1$.

$$y=1$$

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{x}{2}+\frac{1}{3}=8$$

Multiply both sides of the equation by $6$, the least common multiple of $2,3$.

$$3x+2=48$$

Subtract $2$ from both sides.

$$3x=48-2$$

Subtract $2$ from $48$ to get $46$.

$$3x=46$$

Divide both sides by $3$.

$$x=\frac{46}{3}$$

The system is now solved.

$$x=\frac{46}{3}$$ $$y=1$$