How to solve 3 8 و 4 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 8 و 4 6 | Equatix

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Question

$$\frac { x } { 3 } + \frac { y } { 4 } = 4 ; \frac { 5 x } { 6 } - \frac { 4 } { 8 } = 4$$

Solve for x, y

$x = \frac{27}{5} = 5\frac{2}{5} = 5.4$
$y = \frac{44}{5} = 8\frac{4}{5} = 8.8$

Solution Steps

Consider the second equation. Multiply both sides of the equation by $24$, the least common multiple of $6,8$.

$$4\times 5x-3\times 4=96$$

Multiply $4$ and $5$ to get $20$.

$$20x-3\times 4=96$$

Multiply $-3$ and $4$ to get $-12$.

$$20x-12=96$$

Add $12$ to both sides.

$$20x=96+12$$

Add $96$ and $12$ to get $108$.

$$20x=108$$

Divide both sides by $20$.

$$x=\frac{108}{20}$$

Reduce the fraction $\frac{108}{20}$ to lowest terms by extracting and canceling out $4$.

$$x=\frac{27}{5}$$

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{\frac{27}{5}}{3}+\frac{y}{4}=4$$

Multiply both sides of the equation by $12$, the least common multiple of $3,4$.

$$4\times \frac{27}{5}+3y=48$$

Multiply $4$ and $\frac{27}{5}$ to get $\frac{108}{5}$.

$$\frac{108}{5}+3y=48$$

Subtract $\frac{108}{5}$ from both sides.

$$3y=48-\frac{108}{5}$$

Subtract $\frac{108}{5}$ from $48$ to get $\frac{132}{5}$.

$$3y=\frac{132}{5}$$

Divide both sides by $3$.

$$y=\frac{\frac{132}{5}}{3}$$

Express $\frac{\frac{132}{5}}{3}$ as a single fraction.

$$y=\frac{132}{5\times 3}$$

Multiply $5$ and $3$ to get $15$.

$$y=\frac{132}{15}$$

Reduce the fraction $\frac{132}{15}$ to lowest terms by extracting and canceling out $3$.

$$y=\frac{44}{5}$$

The system is now solved.

$$x=\frac{27}{5}$$ $$y=\frac{44}{5}$$

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