Solve x/4 + (x + 2)/3 + (x + 3)/2 = 0 then the value of x | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac { x } { 4 } + \frac { x + 2 } { 3 } + \frac { x + 3 } { 2 } = 0 x$$

Solve for x

$x=-2$

Steps for Solving Linear Equation

Multiply both sides of the equation by $12$, the least common multiple of $4,3,2$.

$$3x+4\left(x+2\right)+6\left(x+3\right)=0x$$

Use the distributive property to multiply $4$ by $x+2$.

$$3x+4x+8+6\left(x+3\right)=0x$$

Combine $3x$ and $4x$ to get $7x$.

$$7x+8+6\left(x+3\right)=0x$$

Use the distributive property to multiply $6$ by $x+3$.

$$7x+8+6x+18=0x$$

Combine $7x$ and $6x$ to get $13x$.

$$13x+8+18=0x$$

Add $8$ and $18$ to get $26$.

$$13x+26=0x$$

Anything times zero gives zero.

$$13x+26=0$$

Subtract $26$ from both sides. Anything subtracted from zero gives its negation.

$$13x=-26$$

Divide both sides by $13$.

$$x=\frac{-26}{13}$$

Divide $-26$ by $13$ to get $-2$.

$$x=-2$$