Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac{ x }{ 6 } + \frac{ x }{ 3 } \leq \frac{ x }{ 4 }$$

Answer

x<=0

Solution


Simplify  \(\frac{x}{6}+\frac{x}{3}\)  to  \(\frac{x}{2}\).
\[\frac{x}{2}\le \frac{x}{4}\]
Multiply both sides by \(4\) (the LCM of \(2, 4\)).
\[2x\le x\]
Subtract \(x\) from both sides.
\[2x-x\le 0\]
Simplify  \(2x-x\)  to  \(x\).
\[x\le 0\]
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