How to solve x/9 - 8 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x/9 - 8 = | Equatix

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$$\frac{x}{9}-8=$$

$\frac{x}{9}-8$

To add or subtract expressions, expand them to make their denominators the same. Multiply $8$ times $\frac{9}{9}$.

$$\frac{x}{9}-\frac{8\times 9}{9}$$

Since $\frac{x}{9}$ and $\frac{8\times 9}{9}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{x-8\times 9}{9}$$

Do the multiplications in $x-8\times 9$.

$$\frac{x-72}{9}$$

$\frac{x-72}{9}$