$$\frac{ x-1 }{ 2 } - \frac{ x2 }{ 3 } - \frac{ x-3 }{ 4 } =- \frac{ x-5 }{ 6 }$$
$x=\frac{4x_{2}+7}{5}$
$$6\left(x-1\right)-4x_{2}-3\left(x-3\right)=-2\left(x-5\right)$$
$$6x-6-4x_{2}-3\left(x-3\right)=-2\left(x-5\right)$$
$$6x-6-4x_{2}-3x+9=-2\left(x-5\right)$$
$$3x-6-4x_{2}+9=-2\left(x-5\right)$$
$$3x+3-4x_{2}=-2\left(x-5\right)$$
$$3x+3-4x_{2}=-2x+10$$
$$3x+3-4x_{2}+2x=10$$
$$5x+3-4x_{2}=10$$
$$5x-4x_{2}=10-3$$
$$5x-4x_{2}=7$$
$$5x=7+4x_{2}$$
$$5x=4x_{2}+7$$
$$\frac{5x}{5}=\frac{4x_{2}+7}{5}$$
$$x=\frac{4x_{2}+7}{5}$$
Show Solution
Hide Solution
$x_{2}=\frac{5x-7}{4}$
$$3-4x_{2}=-2x+10-3x$$
$$3-4x_{2}=-5x+10$$
$$-4x_{2}=-5x+10-3$$
$$-4x_{2}=-5x+7$$
$$-4x_{2}=7-5x$$
$$\frac{-4x_{2}}{-4}=\frac{7-5x}{-4}$$
$$x_{2}=\frac{7-5x}{-4}$$
$$x_{2}=\frac{5x-7}{4}$$
