$$\frac { x - 1 } { 3 } - \frac { 1 } { 12 } = \frac { 4 x + 1 } { 4 }$$
$x=-1$
$$4\left(x-1\right)-1=3\left(4x+1\right)$$
$$4x-4-1=3\left(4x+1\right)$$
$$4x-5=3\left(4x+1\right)$$
$$4x-5=12x+3$$
$$4x-5-12x=3$$
$$-8x-5=3$$
$$-8x=3+5$$
$$-8x=8$$
$$x=\frac{8}{-8}$$
$$x=-1$$
Show Solution
Hide Solution
