$$\frac{ x-3 }{ 3-2 } = \frac{ y-4 }{ 4-(-3) }$$
$x=\frac{y+17}{7}$
$$\frac{x-3}{1}=\frac{y-4}{4-\left(-3\right)}$$
$$x-3=\frac{y-4}{4-\left(-3\right)}$$
$$x-3=\frac{y-4}{4+3}$$
$$x-3=\frac{y-4}{7}$$
$$x-3=\frac{1}{7}y-\frac{4}{7}$$
$$x=\frac{1}{7}y-\frac{4}{7}+3$$
$$x=\frac{1}{7}y+\frac{17}{7}$$
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$y=7x-17$
$$\frac{1}{7}y-\frac{4}{7}=x-3$$
$$\frac{1}{7}y=x-3+\frac{4}{7}$$
$$\frac{1}{7}y=x-\frac{17}{7}$$
$$\frac{\frac{1}{7}y}{\frac{1}{7}}=\frac{x-\frac{17}{7}}{\frac{1}{7}}$$
$$y=\frac{x-\frac{17}{7}}{\frac{1}{7}}$$
$$y=7x-17$$
