$$\frac{x-3}{3-2}=\frac{y-4}{9-(-3)}$$
$x=\frac{y+32}{12}$
$$\frac{x-3}{1}=\frac{y-4}{9-\left(-3\right)}$$
$$x-3=\frac{y-4}{9-\left(-3\right)}$$
$$x-3=\frac{y-4}{9+3}$$
$$x-3=\frac{y-4}{12}$$
$$x-3=\frac{1}{12}y-\frac{1}{3}$$
$$x=\frac{1}{12}y-\frac{1}{3}+3$$
$$x=\frac{1}{12}y+\frac{8}{3}$$
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$y=12x-32$
$$\frac{1}{12}y-\frac{1}{3}=x-3$$
$$\frac{1}{12}y=x-3+\frac{1}{3}$$
$$\frac{1}{12}y=x-\frac{8}{3}$$
$$\frac{\frac{1}{12}y}{\frac{1}{12}}=\frac{x-\frac{8}{3}}{\frac{1}{12}}$$
$$y=\frac{x-\frac{8}{3}}{\frac{1}{12}}$$
$$y=12x-32$$
