Question

$$\frac{ x-3 }{ 5 } \frac{ .10 }{ 7x-21 }$$

Answer

0.0028571428571429

Solution


Factor out the common term \(7\).
\[\frac{x-3}{5}\times \frac{.10}{7(x-3)}\]
Cancel \(x-3\).
\[\frac{1}{5}\times \frac{.10}{7}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{1\times .10}{5\times 7}\]
Simplify  \(1\times .10\)  to  \(0.1\).
\[\frac{0.1}{5\times 7}\]
Simplify  \(5\times 7\)  to  \(35\).
\[\frac{0.1}{35}\]
Simplify.
\[0.002857\]