Question

$$\frac{x-4}{2}=\frac{(x+2)^{2}-x^{2}}{3}$$

Answer

x=-4

Solution


Multiply both sides by \(6\) (the LCM of \(2, 3\)).
\[3(x-4)=8(x+1)\]
Expand.
\[3x-12=8x+8\]
Subtract \(3x\) from both sides.
\[-12=8x+8-3x\]
Simplify  \(8x+8-3x\)  to  \(5x+8\).
\[-12=5x+8\]
Subtract \(8\) from both sides.
\[-12-8=5x\]
Simplify  \(-12-8\)  to  \(-20\).
\[-20=5x\]
Divide both sides by \(5\).
\[-\frac{20}{5}=x\]
Simplify  \(\frac{20}{5}\)  to  \(4\).
\[-4=x\]
Switch sides.
\[x=-4\]