$$\frac{x-6}{2}; \frac{x-3}{9}$$
$x = \frac{48}{7} = 6\frac{6}{7} \approx 6.857142857$
$$9\left(x-6\right)=2\left(x-3\right)$$
$$9x-54=2\left(x-3\right)$$
$$9x-54=2x-6$$
$$9x-54-2x=-6$$
$$7x-54=-6$$
$$7x=-6+54$$
$$7x=48$$
$$x=\frac{48}{7}$$
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