$$\frac { x ( 3 k - 1 ) - 2 k + 1 } { 7 k - 2 } = \frac { 1 } { 2 }$$
$k=-\frac{2\left(2-x\right)}{6x-11}$
$x\neq 3\text{ and }x\neq \frac{11}{6}$
$x=-\frac{4-11k}{2\left(3k-1\right)}$
$k\neq \frac{1}{3}\text{ and }k\neq \frac{2}{7}$
