Question

$$\frac{x+1}{2}+\frac{x+2}{3}+\frac{x-5}{4}=\frac{x}{12}$$

Answer

x=1/12

Solution


Multiply both sides by \(12\) (the LCM of \(2, 3, 4, 12\)).
\[6(x+1)+4(x+2)+3(x-5)=x\]
Expand.
\[6x+6+4x+8+3x-15=x\]
Simplify  \(6x+6+4x+8+3x-15\)  to  \(13x-1\).
\[13x-1=x\]
Subtract \(13x\) from both sides.
\[-1=x-13x\]
Simplify  \(x-13x\)  to  \(-12x\).
\[-1=-12x\]
Divide both sides by \(-12\).
\[\frac{-1}{-12}=x\]
Two negatives make a positive.
\[\frac{1}{12}=x\]
Switch sides.
\[x=\frac{1}{12}\]

Decimal Form: 0.083333