How to solve (x + 1)/3 < x/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x + 1)/3 < x/4 | Equatix

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$$\frac{x+1}{3}<\frac{x}{4}$$

$x<-4$

Multiply both sides of the equation by $12$, the least common multiple of $3,4$. Since $12$ is positive, the inequality direction remains the same.

$$4\left(x+1\right)<3x$$

Use the distributive property to multiply $4$ by $x+1$.

$$4x+4<3x$$

Subtract $3x$ from both sides.

$$4x+4-3x<0$$

Combine $4x$ and $-3x$ to get $x$.

$$x+4<0$$

Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$x<-4$$