Question

$$\frac{x+1}{7}+x=\frac{3x-4}{14}+6$$

Answer

x=6

Solution


Multiply both sides by \(14\) (the LCM of \(7, 14\)).
\[2(x+1)+14x=3x-4+84\]
Simplify  \(3x-4+84\)  to  \(3x+80\).
\[2(x+1)+14x=3x+80\]
Expand.
\[2x+2+14x=3x+80\]
Simplify  \(2x+2+14x\)  to  \(16x+2\).
\[16x+2=3x+80\]
Subtract \(2\) from both sides.
\[16x=3x+80-2\]
Simplify  \(3x+80-2\)  to  \(3x+78\).
\[16x=3x+78\]
Subtract \(3x\) from both sides.
\[16x-3x=78\]
Simplify  \(16x-3x\)  to  \(13x\).
\[13x=78\]
Divide both sides by \(13\).
\[x=\frac{78}{13}\]
Simplify  \(\frac{78}{13}\)  to  \(6\).
\[x=6\]