$$\frac{ x+2 }{ 3 } = \frac{ y-2 }{ 4 } = \frac{ y-x }{ 3 }$$
$\frac{x+2}{3}=\frac{y-2}{4}\text{ and }\frac{y-2}{4}=\frac{y-x}{3}$
$x=4$
$y=10$
$y=10$
$x=4$
