$$\frac{ x+2 }{ x-2 } \div \frac{ { x }^{ 2 } +3x+2 }{ x-2 } \times \frac{ x+1 }{ x+3 }$$
$\frac{1}{x+3}$
$$\frac{\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x^{2}+3x+2\right)}\times \frac{x+1}{x+3}$$
$$\frac{x+2}{x^{2}+3x+2}\times \frac{x+1}{x+3}$$
$$\frac{x+2}{\left(x+1\right)\left(x+2\right)}\times \frac{x+1}{x+3}$$
$$\frac{1}{x+1}\times \frac{x+1}{x+3}$$
$$\frac{x+1}{\left(x+1\right)\left(x+3\right)}$$
$$\frac{1}{x+3}$$
Show Solution
Hide Solution
