$$\frac{ x+3 }{ 4 } - \frac{ x }{ 3 } \geq 1- \frac{ 3x-1 }{ 2 }$$
$x\geq \frac{9}{17}$
$$3\left(x+3\right)-4x\geq 12-6\left(3x-1\right)$$
$$3x+9-4x\geq 12-6\left(3x-1\right)$$
$$-x+9\geq 12-6\left(3x-1\right)$$
$$-x+9\geq 12-18x+6$$
$$-x+9\geq 18-18x$$
$$-x+9+18x\geq 18$$
$$17x+9\geq 18$$
$$17x\geq 18-9$$
$$17x\geq 9$$
$$x\geq \frac{9}{17}$$
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