Question

$$\frac{x+y-7}{3}=\frac{2x-y+1}{5}=\frac{3x+y*11}{7}$$

Evaluate (complex solution)

$\frac{x+y-7}{3}=\frac{2x-y+1}{5}\text{ and }\frac{2x-y+1}{5}=\frac{3x+11y}{7}$

Solve for x

$x = -\frac{230}{7} = -32\frac{6}{7} \approx -32.857142857$
$y = \frac{9}{14} = 0.6428571428571429$

Solve for y

$y = \frac{9}{14} = 0.6428571428571429$
$x = -\frac{230}{7} = -32\frac{6}{7} = -32.857142857142854$