$$\frac{x^{2}}{4}-4x+16$$
$\frac{\left(x-8\right)^{2}}{4}$
$$\frac{x^{2}}{4}+\frac{4\left(-4x+16\right)}{4}$$
$$\frac{x^{2}+4\left(-4x+16\right)}{4}$$
$$\frac{x^{2}-16x+64}{4}$$
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$$\left(x-8\right)^{2}$$
$$\frac{\left(x-8\right)^{2}}{4}$$