$$\frac { x ^ { 2 } } { 8 }$$
$\frac{x}{4}$
$$2\times \frac{1}{8}x^{2-1}$$
$$\frac{1}{4}x^{2-1}$$
$$\frac{1}{4}x^{1}$$
$$\frac{1}{4}x$$
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$\frac{x^{2}}{8}$