How to solve (x ^ 2)/y - 4y

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x ^ 2)/y - 4y | Equatix

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$$\frac{x^{2}}{y}-4y$$

$\frac{x^{2}}{y}-4y$

To add or subtract expressions, expand them to make their denominators the same. Multiply $-4y$ times $\frac{y}{y}$.

$$\frac{x^{2}}{y}+\frac{-4yy}{y}$$

Since $\frac{x^{2}}{y}$ and $\frac{-4yy}{y}$ have the same denominator, add them by adding their numerators.

$$\frac{x^{2}-4yy}{y}$$

Do the multiplications in $x^{2}-4yy$.

$$\frac{x^{2}-4y^{2}}{y}$$

$\frac{\left(-x-2y\right)\left(2y-x\right)}{y}$