Variable $x$ cannot be equal to $0$ since division by zero is not defined. Multiply both sides of the equation by $x$.
$$x^{2}-2x=0$$
Factor out $x$.
$$x\left(x-2\right)=0$$
To find equation solutions, solve $x=0$ and $x-2=0$.
$$x=0$$ $$x=2$$
Variable $x$ cannot be equal to $0$.
$$x=2$$
Steps Using the Quadratic Formula
Variable $x$ cannot be equal to $0$ since division by zero is not defined. Multiply both sides of the equation by $x$.
$$x^{2}-2x=0$$
This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $-2$ for $b$, and $0$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.
Now solve the equation $x=\frac{2±2}{2}$ when $±$ is plus. Add $2$ to $2$.
$$x=\frac{4}{2}$$
Divide $4$ by $2$.
$$x=2$$
Now solve the equation $x=\frac{2±2}{2}$ when $±$ is minus. Subtract $2$ from $2$.
$$x=\frac{0}{2}$$
Divide $0$ by $2$.
$$x=0$$
The equation is now solved.
$$x=2$$ $$x=0$$
Variable $x$ cannot be equal to $0$.
$$x=2$$
Steps for Completing the Square
Variable $x$ cannot be equal to $0$ since division by zero is not defined. Multiply both sides of the equation by $x$.
$$x^{2}-2x=0$$
Divide $-2$, the coefficient of the $x$ term, by $2$ to get $-1$. Then add the square of $-1$ to both sides of the equation. This step makes the left hand side of the equation a perfect square.
$$x^{2}-2x+1=1$$
Factor $x^{2}-2x+1$. In general, when $x^{2}+bx+c$ is a perfect square, it can always be factored as $\left(x+\frac{b}{2}\right)^{2}$.
$$\left(x-1\right)^{2}=1$$
Take the square root of both sides of the equation.
