Divide $\frac{x^{2}-9}{x^{2}-3x-18}$ by $\frac{x^{2}-5x+6}{x^{2}+4x-12}$ by multiplying $\frac{x^{2}-9}{x^{2}-3x-18}$ by the reciprocal of $\frac{x^{2}-5x+6}{x^{2}+4x-12}$.
Divide $\frac{x^{2}-9}{x^{2}-3x-18}$ by $\frac{x^{2}-5x+6}{x^{2}+4x-12}$ by multiplying $\frac{x^{2}-9}{x^{2}-3x-18}$ by the reciprocal of $\frac{x^{2}-5x+6}{x^{2}+4x-12}$.