$$\frac { x ^ { 2 } + 3 } { x ^ { 2 } - 9 } = \frac { x } { x + 3 }$$
Solve for x
$x=-1$
Steps for Solving Linear Equation
Variable $x$ cannot be equal to any of the values $-3,3$ since division by zero is not defined. Multiply both sides of the equation by $\left(x-3\right)\left(x+3\right)$, the least common multiple of $x^{2}-9,x+3$.
$$x^{2}+3=\left(x-3\right)x$$
Use the distributive property to multiply $x-3$ by $x$.
$$x^{2}+3=x^{2}-3x$$
Subtract $x^{2}$ from both sides.
$$x^{2}+3-x^{2}=-3x$$
Combine $x^{2}$ and $-x^{2}$ to get $0$.
$$3=-3x$$
Swap sides so that all variable terms are on the left hand side.
