$$\frac { x ^ { 2 } + 7 x + 10 } { x + 6 } \cdot \frac { 6 x - 6 } { x ^ { 2 } + 2 x - 15 }$$
$\frac{6\left(x-1\right)\left(x+2\right)}{\left(x-3\right)\left(x+6\right)}$
$$\frac{\left(x^{2}+7x+10\right)\left(6x-6\right)}{\left(x+6\right)\left(x^{2}+2x-15\right)}$$
$$\frac{6\left(x-1\right)\left(x+2\right)\left(x+5\right)}{\left(x-3\right)\left(x+5\right)\left(x+6\right)}$$
$$\frac{6\left(x-1\right)\left(x+2\right)}{\left(x-3\right)\left(x+6\right)}$$
$$\frac{6x^{2}+6x-12}{x^{2}+3x-18}$$
Show Solution
Hide Solution
$\frac{6\left(x^{2}+x-2\right)}{\left(x-3\right)\left(x+6\right)}$