$$\frac{x^{2}+7x+10}{bx+6}\cdot\frac{6x-6}{x^{2}+2x-15}$$
$\frac{6\left(x-1\right)\left(x+2\right)}{\left(x-3\right)\left(bx+6\right)}$
$\frac{6\left(x^{2}+x-2\right)}{\left(x-3\right)\left(bx+6\right)}$