$$\frac{x^{2}+x}{4}-\frac{3-7x}{20}=0,3.$$
$x=\frac{-\sqrt{51}-6}{5}\approx -2.628285686\text{, }y=3$
$x=\frac{\sqrt{51}-6}{5}\approx 0.228285686\text{, }y=3$
