$$\frac { x ^ { 3 } } { 8 + \sqrt { 4 } }$$
$\frac{x^{3}}{10}$
$$\frac{x^{3}}{8+2}$$
$$\frac{x^{3}}{10}$$
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$\frac{3x^{2}}{10}$
$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x^{3}}{8+2})$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x^{3}}{10})$$
$$3\times \frac{1}{10}x^{3-1}$$
$$\frac{3}{10}x^{3-1}$$
$$\frac{3}{10}x^{2}$$
