$$\frac { x ^ { 3 } - 2 x ^ { 2 } } { 3 x + 3 } : \frac { x ^ { 2 } - 4 } { 3 x ^ { 2 } + 9 x + 6 }$$
Evaluate
$x^{2}$
Short Solution Steps
Divide $\frac{x^{3}-2x^{2}}{3x+3}$ by $\frac{x^{2}-4}{3x^{2}+9x+6}$ by multiplying $\frac{x^{3}-2x^{2}}{3x+3}$ by the reciprocal of $\frac{x^{2}-4}{3x^{2}+9x+6}$.
Divide $\frac{x^{3}-2x^{2}}{3x+3}$ by $\frac{x^{2}-4}{3x^{2}+9x+6}$ by multiplying $\frac{x^{3}-2x^{2}}{3x+3}$ by the reciprocal of $\frac{x^{2}-4}{3x^{2}+9x+6}$.
