$$\frac { x ^ { 4 } + 7 x + 10 } { x + 6 } \cdot \frac { 6 x - 6 } { x ^ { 2 } + 2 x - 15 }$$
$\frac{6\left(x-1\right)\left(x^{4}+7x+10\right)}{\left(x-3\right)\left(x+5\right)\left(x+6\right)}$
$\frac{6\left(x^{5}-x^{4}+7x^{2}+3x-10\right)}{\left(x+6\right)\left(x^{2}+2x-15\right)}$
