$$\frac{ y-0 }{ 0-(-3) } = \frac{ x-0 }{ 0-(-7) }$$
$x=\frac{7y}{3}$
$$\frac{y-0}{0+3}=\frac{x-0}{0-\left(-7\right)}$$
$$\frac{y-0}{3}=\frac{x-0}{0-\left(-7\right)}$$
$$\frac{y-0}{3}=\frac{x-0}{0+7}$$
$$\frac{y-0}{3}=\frac{x-0}{7}$$
$$\frac{1}{3}y-0=\frac{x-0}{7}$$
$$\frac{1}{3}y-0=\frac{1}{7}x-0$$
$$\frac{1}{7}x-0=\frac{1}{3}y-0$$
$$\frac{1}{7}x=\frac{1}{3}y-0+0$$
$$\frac{1}{7}x=\frac{1}{3}y-0$$
$$\frac{1}{7}x=\frac{1}{3}y$$
$$\frac{1}{7}x=\frac{y}{3}$$
$$\frac{\frac{1}{7}x}{\frac{1}{7}}=\frac{y}{\frac{1}{7}\times 3}$$
$$x=\frac{y}{\frac{1}{7}\times 3}$$
$$x=\frac{7y}{3}$$
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$y=\frac{3x}{7}$
$$\frac{1}{3}y=\frac{1}{7}x-0+0$$
$$\frac{1}{3}y=\frac{1}{7}x-0$$
$$\frac{1}{3}y=\frac{1}{7}x$$
$$\frac{1}{3}y=\frac{x}{7}$$
$$\frac{\frac{1}{3}y}{\frac{1}{3}}=\frac{x}{\frac{1}{3}\times 7}$$
$$y=\frac{x}{\frac{1}{3}\times 7}$$
$$y=\frac{3x}{7}$$
