$$\frac{ y-3 }{ 3 } = \frac{ y+5 }{ 4 }$$
$y=27$
$$4\left(y-3\right)=3\left(y+5\right)$$
$$4y-12=3\left(y+5\right)$$
$$4y-12=3y+15$$
$$4y-12-3y=15$$
$$y-12=15$$
$$y=15+12$$
$$y=27$$
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