$$\frac{y^{2}}{y^{2}-3y-28}-\frac{12-y}{y^{2}-3y-28}$$
$\frac{y-3}{y-7}$
$$\frac{y^{2}-\left(12-y\right)}{y^{2}-3y-28}$$
$$\frac{y^{2}-12+y}{y^{2}-3y-28}$$
$$\frac{\left(y-3\right)\left(y+4\right)}{\left(y-7\right)\left(y+4\right)}$$
$$\frac{y-3}{y-7}$$
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