How to solve z/4 = (z + 15)/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve z/4 = (z + 15)/9 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{z}{4}=\frac{z+15}{9}$$

Solve for z

$z=12$

Steps for Solving Linear Equation

Multiply both sides of the equation by $36$, the least common multiple of $4,9$.

$$9z=4\left(z+15\right)$$

Use the distributive property to multiply $4$ by $z+15$.

$$9z=4z+60$$

Subtract $4z$ from both sides.

$$9z-4z=60$$

Combine $9z$ and $-4z$ to get $5z$.

$$5z=60$$

Divide both sides by $5$.

$$z=\frac{60}{5}$$

Divide $60$ by $5$ to get $12$.

$$z=12$$

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Solve for z

Steps for Solving Linear Equation