$$f(2)=\binom{4}{2}(\frac{1}{4})^{2}(\frac{3}{4})^{4-2}=$$
$\frac{9}{128}=0.0703125$
$$2\times \left(\frac{1}{4}\right)^{2}\times \left(\frac{3}{4}\right)^{4-2}$$
$$2\times \frac{1}{16}\times \left(\frac{3}{4}\right)^{4-2}$$
$$\frac{1}{8}\times \left(\frac{3}{4}\right)^{4-2}$$
$$\frac{1}{8}\times \left(\frac{3}{4}\right)^{2}$$
$$\frac{1}{8}\times \frac{9}{16}$$
$$\frac{9}{128}$$
Show Solution
Hide Solution
$\frac{3 ^ {2}}{2 ^ {7}} = 0.0703125$
