$$f(3)=\binom{4}{3}(\frac{1}{4})^{3}(\frac{3}{4})^{4-3}=$$
$\frac{1}{64}=0.015625$
$$\frac{4}{3}\times \frac{1}{64}\times \left(\frac{3}{4}\right)^{4-3}$$
$$\frac{1}{48}\times \left(\frac{3}{4}\right)^{4-3}$$
$$\frac{1}{48}\times \left(\frac{3}{4}\right)^{1}$$
$$\frac{1}{48}\times \frac{3}{4}$$
$$\frac{1}{64}$$
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$\frac{1}{2 ^ {6}} = 0.015625$
