$$f(\frac{3}{4})=2(\frac{3}{4})^{2}-4(\frac{3}{4})+16$$
$\frac{113}{8}=14.125$
$$2\times \frac{9}{16}-4\times \frac{3}{4}+16$$
$$\frac{2\times 9}{16}-4\times \frac{3}{4}+16$$
$$\frac{18}{16}-4\times \frac{3}{4}+16$$
$$\frac{9}{8}-4\times \frac{3}{4}+16$$
$$\frac{9}{8}-3+16$$
$$\frac{9}{8}-\frac{24}{8}+16$$
$$\frac{9-24}{8}+16$$
$$-\frac{15}{8}+16$$
$$-\frac{15}{8}+\frac{128}{8}$$
$$\frac{-15+128}{8}$$
$$\frac{113}{8}$$
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$\frac{113}{2 ^ {3}} = 14\frac{1}{8} = 14.125$
