$$f ( x ) = 4 x ^ { 3 } + 9 x ^ { 2 } + 3 x - 7 \quad g ( x ) = x + 1$$
$g=\frac{4x^{2}}{7}+\frac{9x}{7}+\frac{2}{7}-\frac{1}{7x}$
$x\neq 0$
