Solve f(x) = - 2x ^ 2 + 8 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$f(x)=-2x^{2}+8$$

Factor

$2\left(-x-2\right)\left(x-2\right)$

Solution Steps

Factor out $2$.

$$2\left(-x^{2}+4\right)$$

Consider $-x^{2}+4$. Rewrite $-x^{2}+4$ as $2^{2}-x^{2}$. The difference of squares can be factored using the rule: $a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$.

$$\left(2-x\right)\left(2+x\right)$$

Reorder the terms.

$$\left(-x+2\right)\left(x+2\right)$$

Rewrite the complete factored expression.

$$2\left(-x+2\right)\left(x+2\right)$$

Evaluate

$8-2x^{2}$