Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$f ( x ) = \sin x - \frac { 1 } { 2 } \cos 2 x \quad [ 0 , 2 \pi ]$$

Answer

f=(sin(x)-(o*n[0*cos(2*x))/2)/x,(2*nsiderthefunctio*PI]o*n)/x

Solution


f*x=sin(x)-(cos(2*x)*o*n\(0\)o*nsiderthefunctio*n
Regroup terms.
f*x=sin(x)-(o*n\(0\cos{2x}\)o*nsiderthefunctio*n
Regroup terms.
f*x=sin(x)-(o*n\(0\cos{2x}\)o*n
Break down the problem into these 2 equations.
Collect all solutions.
f=(sin(x)-(o*n\(0\cos{2x}\)o*n)/x
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