Solve F(x)=x^ 3 +ux^ 2 -3x+10,90x]=x+C | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$F(x)=x^{3}+ux^{2}-3x+10,90x]=x+C$$

Solve for F, x

$x=900$
$F = \frac{73385731}{90} = 815397\frac{1}{90} \approx 815397.011111111$

Solution Steps

Consider the second equation. Anything plus zero gives itself.

$$900=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=900$$

Consider the first equation. Insert the known values of variables into the equation.

$$F\times 900=900^{3}+6\times 900^{2}-3\times 900+10$$

Calculate $900$ to the power of $3$ and get $729000000$.

$$F\times 900=729000000+6\times 900^{2}-3\times 900+10$$

Calculate $900$ to the power of $2$ and get $810000$.

$$F\times 900=729000000+6\times 810000-3\times 900+10$$

Multiply $6$ and $810000$ to get $4860000$.

$$F\times 900=729000000+4860000-3\times 900+10$$

Add $729000000$ and $4860000$ to get $733860000$.

$$F\times 900=733860000-3\times 900+10$$

Multiply $-3$ and $900$ to get $-2700$.

$$F\times 900=733860000-2700+10$$

Subtract $2700$ from $733860000$ to get $733857300$.

$$F\times 900=733857300+10$$

Add $733857300$ and $10$ to get $733857310$.

$$F\times 900=733857310$$

Divide both sides by $900$.

$$F=\frac{733857310}{900}$$

Reduce the fraction $\frac{733857310}{900}$ to lowest terms by extracting and canceling out $10$.

$$F=\frac{73385731}{90}$$

The system is now solved.

$$F=\frac{73385731}{90}$$ $$x=900$$