Question

$$g 3 x ^ { 3 } y \sqrt { 3 } x y ^ { 2 } ,$$

Answer

$$3*sqrt(3)*x^4*y^4*b,t*h$$

Solution


Regroup terms.
\[3{x}^{3}xyy{y}^{2}b\sqrt{3},th\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[3{x}^{3+1}{y}^{1+1+2}b\sqrt{3},th\]
Simplify  \(3+1\)  to  \(4\).
\[3{x}^{4}{y}^{1+1+2}b\sqrt{3},th\]
Simplify  \(1+1\)  to  \(2\).
\[3{x}^{4}{y}^{2+2}b\sqrt{3},th\]
Simplify  \(2+2\)  to  \(4\).
\[3{x}^{4}{y}^{4}b\sqrt{3},th\]
Simplify square root.
\[3\sqrt{3}{x}^{4}{y}^{4}b,th\]