Question

$$G=\frac{\sqrt{(-6)^{2}}-\sqrt{32}}{2+\sqrt{7}\times\sqrt{35}-\sqrt{245}}$$

Answer

G=3-2*sqrt(2)

Solution


Since the power of 2 is even, the result will be positive.
\[G=\frac{\sqrt{{6}^{2}}-\sqrt{32}}{2+\sqrt{7}\sqrt{35}-\sqrt{245}}\]
Simplify  \(\sqrt{{6}^{2}}\)  to  \(6\).
\[G=\frac{6-\sqrt{32}}{2+\sqrt{7}\sqrt{35}-\sqrt{245}}\]
Simplify  \(\sqrt{32}\)  to  \(4\sqrt{2}\).
\[G=\frac{6-4\sqrt{2}}{2+\sqrt{7}\sqrt{35}-\sqrt{245}}\]
Factor out the common term \(2\).
\[G=\frac{2(3-2\sqrt{2})}{2+\sqrt{7}\sqrt{35}-\sqrt{245}}\]
Simplify  \(\sqrt{245}\)  to  \(7\sqrt{5}\).
\[G=\frac{2(3-2\sqrt{2})}{2+\sqrt{7}\sqrt{35}-7\sqrt{5}}\]
Simplify  \(\sqrt{7}\sqrt{35}\)  to  \(\sqrt{245}\).
\[G=\frac{2(3-2\sqrt{2})}{2+\sqrt{245}-7\sqrt{5}}\]
Simplify  \(\sqrt{245}\)  to  \(7\sqrt{5}\).
\[G=\frac{2(3-2\sqrt{2})}{2+7\sqrt{5}-7\sqrt{5}}\]
Simplify  \(2+7\sqrt{5}-7\sqrt{5}\)  to  \(2\).
\[G=\frac{2(3-2\sqrt{2})}{2}\]
Cancel \(2\).
\[G=3-2\sqrt{2}\]

Decimal Form: 0.171573