Question

$$If(x)^{2}-4x; +6glindf(1); -\beta^{\prime}(-1)$$

Answer

$$If*x^2-4*x;+6*g*l*IM*n*d*f*1;+b*t*e*a'$$

Solution


Simplify  \(beta'(-1)\)  to  \(-1\times btea'\).
\[\begin{aligned}&If{x}^{2}-4x\\&+6gl\imath ndf\times 1\\&-(-1\times btea')\end{aligned}\]
Simplify  \(-1\times btea'\)  to  \(-btea'\).
\[\begin{aligned}&If{x}^{2}-4x\\&+6gl\imath ndf\times 1\\&-(-btea')\end{aligned}\]
Remove parentheses.
\[\begin{aligned}&If{x}^{2}-4x\\&+6gl\imath ndf\times 1\\&+btea'\end{aligned}\]