Question

$$\iint(1-x^{3}-3x^{2})dx$$

Answer

$$-n*t*d*x*(1-x^3-3*x^2)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{\imath }^{2}nt(1-{x}^{3}-3{x}^{2})dx\]
Use Square Rule: \({i}^{2}=-1\).
\[-1\times nt(1-{x}^{3}-3{x}^{2})dx\]
Simplify  \(1\times nt(1-{x}^{3}-3{x}^{2})dx\)  to  \(ntdx(1-{x}^{3}-3{x}^{2})\).
\[-ntdx(1-{x}^{3}-3{x}^{2})\]